之前都是开胃菜,这回开始上重点了,难度也开始上来了

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课后习题4

#include <>

typedef unsigned char uchar;

typedef unsigned int uint;

typedef unsigned long ulong;

sbit ADDR0 = P1 ^ 0;

sbit ADDR1 = P1 ^ 1;

sbit ADDR2 = P1 ^ 2;

sbit ADDR3 = P1 ^ 3;

sbit ENLED = P1 ^ 4;

uchar code LedChar[] = {

0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8,

0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E};

uchar LedBuff[6] = {0xFF, 0xC0, 0xC0, 0xC0, 0xC0, 0xC0};

bit flag1s = 0;

uint cnt = 0;

void main(void)

{

ulong sec = 980;

ENLED = 0; // 138总开关打开

ADDR3 = 1; // 选138高8路

TMOD = 0x01;

TH0 = 0xFC;

TL0 = 0x66;

TR0 = 1;

EA = ET0 = 1;

while (1)

{

if (flag1s == 1)

{

flag1s = 0;

sec++;

LedBuff[0] = LedChar[sec % 10];

LedBuff[1] = LedChar[sec / 10 % 10];

LedBuff[2] = LedChar[sec / 100 % 10];

LedBuff[3] = LedChar[sec / 1000 % 10];

LedBuff[4] = LedChar[sec / 10000 % 10];

LedBuff[5] = LedChar[sec / 100000 % 10];

}

}

}

void Timer0_ISR(void) interrupt 1

{

static char i = 5;   // 从高位开始显示

static bit show = 0; // 1=显示;0=不显示,默认从高位开始不显示

TH0 = 0xFC; // 重装初值

TL0 = 0x66;

if (++cnt >= 200) // 判断1s到了,为了加快测试把1000改成了200

{

cnt = 0;

flag1s = 1;

}

P0 = 0xFF; // 消影,,,,,后面不显示的部分,也利用了这一次的赋值

switch (i)

{

case 0:

ADDR2 = 0;

ADDR1 = 0;

ADDR0 = 0;

i = 5;

P0 = LedBuff[0]; // 永远会显示

show = 0;

break;

case 1:

ADDR2 = 0;

ADDR1 = 0;

ADDR0 = 1;

i--;

if (show || (LedBuff[1] != LedChar[0]))

{

P0 = LedBuff[1];

show = 1;

}

break;

case 2:

ADDR2 = 0;

ADDR1 = 1;

ADDR0 = 0;

i--;

if (show || (LedBuff[2] != LedChar[0]))

{

P0 = LedBuff[2];

show = 1;

}

break;

case 3:

ADDR2 = 0;

ADDR1 = 1;

ADDR0 = 1;

i--;

if (show || (LedBuff[3] != LedChar[0]))

{

P0 = LedBuff[3];

show = 1;

}

break;

case 4:

ADDR2 = 1;

ADDR1 = 0;

ADDR0 = 0;

i--;

if (show || (LedBuff[4] != LedChar[0]))

{

P0 = LedBuff[4];

show = 1;

}

break;

case 5:

ADDR2 = 1;

ADDR1 = 0;

ADDR0 = 1;

i--;

if (LedBuff[5] != LedChar[0])

{

P0 = LedBuff[5];

show = 1;

}

break;

}

}

课后习题5

#include <>typedef unsigned char uchar;typedef unsigned int uint;typedef unsigned long ulong;sbit ADDR0 = P1 ^ 0;sbit ADDR1 = P1 ^ 1;sbit ADDR2 = P1 ^ 2;sbit ADDR3 = P1 ^ 3;sbit ENLED = P1 ^ 4;uchar code LedChar[] = {    0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8,    0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E};uchar LedBuff[6] = {0x90, 0x90, 0x90, 0x90, 0x90, 0x90};bit flag1s = 0;uint cnt = 0;void main(void){    ulong sec = 999999;    ENLED = 0; // 138总开关打开    ADDR3 = 1; // 选138高8路    TMOD = 0x10;    TH1 = 0xFC;    TL1 = 0x66;    TR1 = 1;    EA = ET1 = 1;    while (1)    {        if (flag1s == 1)        {            flag1s = 0;            sec--;            LedBuff[0] = LedChar[sec % 10];            LedBuff[1] = LedChar[sec / 10 % 10];            LedBuff[2] = LedChar[sec / 100 % 10];            LedBuff[3] = LedChar[sec / 1000 % 10];            LedBuff[4] = LedChar[sec / 10000 % 10];            LedBuff[5] = LedChar[sec / 100000 % 10];        }    }}void Timer1_ISR(void) interrupt 3{    static char i = 0;    TH1 = 0xFC; // 重装初值    TL1 = 0x66;    if (++cnt >= 200) // 判断1s到了;为了加快测试把1000改成了200    {        cnt = 0;        flag1s = 1;    }    P0 = 0xFF; // 消影    switch (i)    {    case 0:        ADDR2 = 0;        ADDR1 = 0;        ADDR0 = 0;        i++;        P0 = LedBuff[0];        break;    case 1:        ADDR2 = 0;        ADDR1 = 0;        ADDR0 = 1;        i++;        P0 = LedBuff[1];        break;    case 2:        ADDR2 = 0;        ADDR1 = 1;        ADDR0 = 0;        i++;        P0 = LedBuff[2];        break;    case 3:        ADDR2 = 0;        ADDR1 = 1;        ADDR0 = 1;        i++;        P0 = LedBuff[3];        break;    case 4:        ADDR2 = 1;        ADDR1 = 0;        ADDR0 = 0;        i++;        P0 = LedBuff[4];        break;    case 5:        ADDR2 = 1;        ADDR1 = 0;        ADDR0 = 1;        i = 0;        P0 = LedBuff[5];        break;    }}

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